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Answer:
1) 943.895 mm3
2) 144 cm3
Step-by-step explanation:
1)
First we need to find the volume of the rectangular prism:
Volume_1 = 9 * 11 * 6 = 594 mm3
Then, we can find the volume of the half cylinder above the prism:
Volume_2 = 0.5*(pi * (4.5^2) * 11) = 349.895 mm3
So the volume of the figure is the sum of both volumes:
Volume_total = Volume_1 + Volume_2 = 943.895 mm3
2)
The volume of a pyramid is one third of the base area multiplied by the height, so we have:
Volume = (1/3) * 6 * 8 * 9 = 144 cm3
Answer:
1. Volume of the composite figure is 943.89 mm³
2. The volume, of the is 144 cm³
Step-by-step explanation:
1. The composite figure comprises of a cube and a half cylinder;
Volume of a cube = 9 mm × 11 mm × 6 mm = 594 mm³
Volume of the half cylinder = area of base × length = (π·r²)/2 × l
Where:
r = (Diameter of base)/2 = 9/2 = 4.5 mm
l = 11 mm
Therefore, plugging the values, gives;
Volume of the half cylinder = (π × 4.5²)/2 × 11 = 349.89 mm³
Hence, volume of the composite figure = Volume of the cube + Volume of the half cylinder
Volume of the composite figure = 594 mm³ + 349.89 mm³ = 943.89 mm³
2. The volume, V of a pyramid is given by the following relation;
[tex]V = \frac{l \times w \times h}{3}[/tex]
Where:
l = Length of base = 8 cm
w = Width of the base = 6 cm
h = Height of the pyramid = 9 cm
[tex]V = \frac{8 \times 6 \times 9}{3} = 144 \ cm^3[/tex]
Here we have that a cube of side x, therefore, the area = x·x, integrating we have;
[tex]\int\limits^x_0 {x \cdot x} \, dx = \frac{x^3}{3}[/tex]
Where:
Length, height width of the pyramid = x
It can therefore be shown, that for a pyramid of length, l, width, w, and height, h, the volume, [tex]V = \frac{l \times w \times h}{3}[/tex] .