Question

WILL MARK BRAINLIEST!!

Answer 1

Answer:

mean = 8.5 mins

median = 9 mins

Step-by-step explanation:

let's form a new table this way

Length of time of spin(mins)   x    4     5      6     7     8     9     10     11

Number of Students                 f     2     1       2     2     2     5      6      4

frequency f = number of students

mean $x_{bar} = \frac{\xi fx}{\xi x}$

hence

$x_{bar} = \frac{4 \times 2 +5\times 1+6\times2+7\times2+8\times2+9\times5+10\times6+11\times4 }{2+1+2+2+2+5+6+4}$

$x_{bar}=\frac{8+5+12+14+16+45+60+44}{24}$

$x_{bar} = \frac{204}{24}$

$x_{bar} = 8.5$

average time the students spent = 8.5 mins

note that

If a data set has an odd number of observations, then the median is the middle value. If it has an even number of observations, the median is the average of the two middle values.

the total no of observation = 24

the median is given by

median = n + 1

                   2

= 24 + 1/2 = 12.5

median is between 12th and the 13th spins

length of time between the 12th and the 13th spins falls between 9 mins