Answer:
1) Answer: 3) [tex]~~x = -3 \pm \sqrt{7}[/tex]
2) Answer: 3) 2 and -6
Step-by-step explanation:
1)
[tex] (x + 3)^2 = 7 [/tex]
[tex] x + 3 = \pm \sqrt{7} [/tex]
[tex] x = -3 \pm \sqrt{7} [/tex]
Answer: [tex] 3)~~x = -3 \pm \sqrt{7} [/tex]
2)
[tex] 2(x + 2)^2 - 4 = 28 [/tex]
[tex] 2(x + 2)^2 = 32 [/tex]
[tex] (x + 2)^2 = 16 [/tex]
[tex] x + 2 = \pm \sqrt{16} [/tex]
[tex] x + 2 = \pm 4 [/tex]
[tex] x + 2 = 4 [/tex] or [tex] x + 2 = -4 [/tex]
[tex] x = 2 [/tex] or [tex] x = -6 [/tex]
Answer: x = 2 or x = -6
