Question

please answer immediately
How many grams of glucose, C6H12O6, are needed to make 100 mL of a 1.5 M solution?

Answer 1

THE ANSWER BOI:

27 g

HERE IS DA EXPLANATION FAM:

27 g

M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol

100 mL = 0.1 L solution

1.5 M = 1.5 mol/L

1.5 mol/L * 0.1 L = 0.15 mol  C6H12O6

0.15 mol * 180 g/1 mol = 27 g C6H12O6