what is the center?
the circle passes through the point (-7,-7). what is the radius?
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We have been given image of circle that passes through point [tex](-7,-7)[/tex]. We are asked to find the radius of the circle.
First of all, we will find the center of the circle.
We can see that center of circle is at point [tex](-2,-1)[/tex].
Now we will use equation of circle to find radius.
[tex](x-h)^2+(y-k)^2=r^2[/tex], where, point (h,k) represents center of circle and r represents radius of circle.
Now we will substitute the coordinates of point [tex](-7,-7)[/tex] and coordinates of center [tex](-2,-1)[/tex] and solve for r as:
[tex](-7+2)^2+(-7+1)^2=r^2[/tex]
[tex](-5)^2+(-6)^2=r^2[/tex]
[tex]25+36=r^2[/tex]
[tex]61=r^2[/tex]
Switch sides:
[tex]r^2=61[/tex]
Now we will take positive square root on both sides:
[tex]\sqrt{r^2}=\sqrt{61}[/tex]
[tex]r=\sqrt{61}[/tex]
Therefore, radius of circle will be [tex]\sqrt{61}[/tex] and center is at point [tex](-2,-1)[/tex].