Respuesta :

We have been given image of circle that passes through point [tex](-7,-7)[/tex]. We are asked to find the radius of the circle.

First of all, we will find the center of the circle.

We can see that center of circle is at point [tex](-2,-1)[/tex].

Now we will use equation of circle to find radius.

[tex](x-h)^2+(y-k)^2=r^2[/tex], where, point (h,k) represents center of circle and r represents radius of circle.

Now we will substitute the coordinates of point [tex](-7,-7)[/tex] and coordinates of center [tex](-2,-1)[/tex] and solve for r as:

[tex](-7+2)^2+(-7+1)^2=r^2[/tex]

[tex](-5)^2+(-6)^2=r^2[/tex]

[tex]25+36=r^2[/tex]

[tex]61=r^2[/tex]

Switch sides:

[tex]r^2=61[/tex]

Now we will take positive square root on both sides:

[tex]\sqrt{r^2}=\sqrt{61}[/tex]

[tex]r=\sqrt{61}[/tex]

Therefore, radius of circle will be [tex]\sqrt{61}[/tex] and center is at point [tex](-2,-1)[/tex].

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