Question

Rewrite the quadratic function from standard form to vertex f(x)=x^2-12x+46?

Answer 1

Answer:

$f(x) = {(x - 6)}^{2} + 10$

explain??:$f(x)={x}^{2}-12 \times x+46 \\

f(x)={x}^{2}-12 \times x+{(-6)}^{2}-{(-6)}^{2}+46\\

f(x)={(x-6)}^{2}-{(-6)}^{2}+46\\

f(x)={(x-6)}^{2}+10\\

f(x)={(x-6)}^{2}+10$