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Solve equations using structure
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Let m = x2 + 3.
Which equation is equivalent to (x2 + 3)2 + 7x2 + 21 =
10 in terms of m?

Respuesta :

Answer: [tex]9m=10[/tex] or [tex]m=\frac{10}{9}[/tex]

I don't know your options... but you can check my work below and see if any of the other options fit yours.

Step-by-step explanation:

[tex](x^2 + 3)2 + 7x^2 + 21 =10[/tex]

If [tex]x^2+3=m[/tex], we can rewrite this as;

[tex](m)2+7x^2+21=10\\2m+7x^2+21=10[/tex]

By grouping, we can factor another m.

[tex]2m+(7x^2+21)=10[/tex]

Factor a 7.

[tex]2m+7(x^2+3)=10[/tex]

Rewrite it in terms of m.

[tex]2m+7m=10[/tex]

Combine like terms;

[tex]9m=10[/tex]

Divide by 9

[tex]m=\frac{10}{9}[/tex]

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