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Find the length of side BY for the given triangle.
option 1- 10 square root 2
option 2- square root 2 over 10
option 3- 5 square root 2
option 4- 5

Find the length of side BY for the given triangle option 1 10 square root 2 option 2 square root 2 over 10 option 3 5 square root 2 option 4 5 class=

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Answer:

option 3- 5 square root 2

Step-by-step explanation:

[tex]\sin 45° = \frac{BY}{OY} \\ \\ \frac{1}{ \sqrt{2} } = \frac{BY}{10} \\ \\ BY = \frac{10}{ \sqrt{2} } \\ \\ BY = \frac{10 \times \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } \\ \\ BY = \frac{10 \sqrt{2} }{2 } \\ \\ \huge \red{ \boxed{BY = 5 \sqrt{2} }}[/tex]

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