What is the sum of the numbers
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Answer:
B 4i sqrt(2)
Step-by-step explanation:
sqrt(-2) = sqrt(-1) * sqrt(2) = i sqrt(2)
sqrt(-18) = sqrt(-1) sqrt(2) sqrt(9) = 3i sqrt(2)
Add them together
i sqrt(2) + 3i sqrt(2)
4i sqrt(2)
Answer:
B.) [tex]4\sqrt{2}i[/tex]
Step-by-step explanation:
Simplify both radicals from negative form (the square root of -1 is i ):
[tex]\sqrt{-1*2} +\sqrt{-1*18} \\\\\sqrt{2}i+\sqrt{18}i[/tex]
Simplify [tex]\sqrt{18}[/tex] :
[tex]\sqrt{9*2}\\\\\sqrt{9}*\sqrt{2}\\\\ 3\sqrt{2}i[/tex]
Add:
[tex]1\sqrt{2}i+3\sqrt{2}i\\\\4\sqrt{2}i[/tex]
:Done