Question

Seven different models cars, from which there are three blue and four red, are to be parked in a row. Find how many different arrangements there are if the first, the last, and the car in the middle of the queue should be blue.

Answer ASAP for brainliest answer!

Answer 1

Answer:144 ways

Step-by-step explanation:

Given

There are 7 different models cars

out of which three are blue and 4 are red

If the first middle and last car in Queue is blue car therefore the position of blue cars is fixed

But these 3 cars can be arranged in 3! ways

Remaining 4 cars can be  arranged in remaining 4 spots in 4! ways

Therefore total no of ways are

$=3!\times 4!$

$=6\times 24=144\ ways$