Question

a gaseous mixture of O2 and N2 has 22.8% of the pressure exerted by N2. What is the partial pressure of oxygen in the mixture, if the total pressure is 785.0 mmHg?

Answer 1

Answer:

The partial pressure of oyxgen O2 is 606 mmHg

Explanation:

Step 1: Data given

Percentage N2 = 22.8 %

The total pressure = 785.0 mmHg

Step 2: Calculate partial pressures

Partial pressure = percentage * total pressure

Partial pressure N2 = 0.228 * 785.0 mmHg

Partial pressure N2 = 179 mmHg

Step 3: Calculate partial pressure O2

Partial pressure O2 = 785.0 mmHg - 179.0 mmHg

Partial pressure O2 = 606 mmHg

OR (1 - 0.228) * 785.0 = 606 mmHg

The partial pressure of oyxgen O2 is 606 mmHg