Question

it takes 26.23 mL of a 1.008 M NaOh solution to neutralize a solution of an unknown monoprotic acid in 150.2 mL of solution. What is the molarity of the unknown?

Answer 1

Answer:

Molarity of acid soln = 0.176M

Explanation:

Molarity of NaOH soln  x  Volume of NaOH soln = Molarity of acid soln  x  Volume of acid soln

=> 26.23ml  x  1.008M  =  150.2ml  x  Molarity of acid solution

=> Molarity of acid soln = (26.23ml)(1.008M)/(150.2ml) = 0.176M

Answer 2

The molarity of the unknown acid is 0.176M.

What is acid?

An acid is a chemical compound with a sour taste and a pH value less than 7.

What is molarity?

• Molarity is the number of moles per litre of solution.
• Molarity is used in calculating  the ratio between the number of moles in the total volume of the solution.
• The unit of molarity is M or Moles L⁻¹

Molarity (M) of the acid x volume (V) of the acid = Molarity (M) of the base x volume (V) of the base.

Molarity of NaOH  x  Volume of NaOH = Molarity of acid   x  Volume of acid

26.23ml  x  1.008M  =  150.2ml  x  Molarity of acid

Molarity of acid  = (26.23ml)(1.008M)/(150.2ml)

                            = 0.176M

Hence, the molarity of the unknown is 0.176M.

To learn more about molarity here

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