Respuesta :
Answer:
B
Explanation:
first find the no. Of moles of H2SO4
= 75/98.1
= 0.7645
Next step
In on mole of H2SO4 the no.of oxygen atom is 4.
1 H2SO4 : 4 O
0.7645 : x x= 0.7645x4= 3.0581
next multiply avogadros constant
3.0581 x 6.022× 10^23 =1.84x10^24
Mass present in 1 gram of mole substance is called molar mass. Molar mass is calculated by: dividing the mass of the compound in grams by the number of moles present in the substances.
The correct answer is:
option B. 1.84 × 10²⁴
Given,
- The mass of sulfuric acid =75.0 g
- The molar mass of sulfuric acid = 98.1 g/mol
1.The moles of sulfuric acid can be calculated by
M = m ÷ n
where M is molar mass, m is mass and n moles.
moles of sulfuric acid = mass ÷ molar mass
= 75 g ÷ 98.1 g/mol
=0.7645 moles
Hence moles of sulfuric acid present is 0.7645 moles.
2. 1 mole of sulfuric acid = 4 oxygen atoms.
Then, 0.7645 moles of sulfuric will contain: 0.7645 × 4 = 3.0581 atoms of oxygen
3. Oxygen atoms present in 75.0 g of H₂SO₄ will be calculated by multiplying it with Avogadro's constant:
= 3.0581 x 6.022× 10²³
= 1.84x10²⁴
Therefore, 1.84 × 10²⁴ oxygen atoms will be found in 75.0 g of H₂SO₄.
To learn more about moles follow the given link:
https://brainly.com/question/20486415
