Answer:
Step-by-step explanation:
Original problem:
2x + 7 > x + 19
Subtract x from both sides.
x + 7 > 19
Subtract 7 from both sides.
x > 12
Problem with 3 instead of 2.
3x + 7 > x + 19
Subtract x from both sides.
2x + 7 > 19
Subtract 7 from both sides.
2x > 12
Divide both sides by 2.
x > 6
2nd question (I'm not sure I understand it correctly.)
x < 3
Solving 2x + 7 > x + 19
2x + 7 > x + 19
Move 7 by subtracting from both sides.
2x > x + 19 - 7
2x > x + 12
Move x by subtracting from both sides.
2x - x > 12
x > 12
Therefore, x is greater than 12.
Solving 3x + 7 > x + 19
3x + 7 > x + 19
Move 7 by subtracting from both sides.
3x > x + 19 -7
3x > x + 12
Move x by subtracting from both sides.
3x - x > 12
2x > 12
Divide 2 on both sides to get x.
2x/2 > 12/2
x > 6
Therefore, x is greater than 6.
Part 2:
Write an expression for if 3 was open inequality and line continues past negative 5. This may not be correct due to the vagueness of what it's asking.
Expression: x < -5 < 3
x indicates all real numbers less -5
3 is open inequality and is the greatest
The 2nd question is like really vague.
