Question

What is the total amount of energy needed to heat 22.6 g of titanium from 1420oC to 1590oC in joules?

Answer 1

Answer:

$Q=2091J=2.091kJ$

Explanation:

Hello,

In this case, the formula we use to compute the heat Q by increasing the temperature, in terms of the mass and the heat capacity is:

$Q=mCp(T_2-T_1)$

Titanium's heat capacity is 0.544284 J/g°C, thus, the for such temperature increase, the heat results positive as shown below:

$Q=22.6g*0.544284\frac{J}{g^oC}*(1590^oC-1420^oC) \\\\Q=2091J=2.091kJ$

Best regards.