Answer:
[tex]V_2=583.3mL[/tex]
Explanation:
Hello,
In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:
[tex]V_2=\frac{V_1T_2}{T_1} =\frac{350.0mL*(227+273.15)K}{(27+273.15)K}\\ \\V_2=583.3mL[/tex]
Best regards.