Answer:
w = 2 and w = 6
Step-by-step explanation:
Given
[tex]\frac{w}{2w-3}[/tex] = [tex]\frac{4}{w}[/tex] ( cross- multiply )
w² = 4(2w - 3) ← distribute
w² = 8w - 12 ( subtract 8w - 12 from both sides )
w² - 8w + 12 = 0 ← in standard form
(w - 2)(w - 6) = 0 ← in factored form
Equate each factor to zero and solve for w
w - 2 = 0 ⇒ w = 2
w - 6 = 0 ⇒ w = 6
