The mass of sulfur trioxide, SO₃, formed is 120 g
The balanced equation for the reaction is given below:
2SO₂ + O₂ —> 2SO₃
Next, we shall determine the mass of SO₂ that reacted and the mass of SO₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of SO₂ = 32 + (16×2)
= 32 + 32
= 64 g /mol
Mass of SO₂ from the balanced equation = 2 × 64 = 128 g
Molar mass of SO₃ = 32 + (16×3)
= 32 + 48
= 80 g /mol
Mass of SO₃ from the balanced equation = 2 × 80 = 160 g
Thus,
From the balanced equation above,
128 g of SO₂ reacted to produce 160 g of SO₃.
Finally, we shall determine the mass of SO₃ by the reaction of 96 g of SO₂. This can be obtained as follow:
From the balanced equation above,
128 g of SO₂ reacted to produce 160 g of SO₃.
Therefore, 96 g of SO₂ will react to produce = [tex]\frac{96 X 160}{128}\\\\[/tex] = 120 g of SO₃.
Therefore, the mass of SO₃ formed is 120 g
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