Question

What mass of solute is needed to prepare each of the following solutions?
a. 1.00 L of 0.125 M K2SO4
b. 375 mL of 0.015 M NaF
c. 500 mL of 0.350 M C6H12O6

Answer 1

Answer:

a. 21.7824 g

b. 0.2362 g

c. 31.5273 g

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Explanation:

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Answer 2

The mass of solute required in each case can be obtained form the stoichiometry of the reaction.

We know that the mass of each solution can be obtained from the relation;

mass/molar mass = concentration × volume

mass = concentration × volume × molar mass

a)

mass =  0.125 M  ×  1.00 L ×  174 g/mol = 21.75 g

b) mass = 0.015 M  × 375 /1000 × 42 g/mol = 0.24 g

c) mass = 0.350 M × 500/1000 × 180 g/mol =31.5 g

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