Question

PLEASE HELP!! DUE!!!!
Write the slope-intercept form of an equation for the line that passes through the given point and is parallel to the graph of the given equation. (−5, 6) and 12x+9y=3

Answer 1

Answer:

The equation is,

$y = - \frac{4}{3}x - \frac{2}{3}$

Step-by-step explanation:

When a line is parallel to the other line, they will have the same gradient :

$12x + 9y = 3$

$9y = - 12x + 3$

$y = - \frac{12}{9} x + \frac{3}{9}$

$y = - \frac{4}{3} x + \frac{1}{3}$

We have already found the gradient. Next, we have to substitute the gradient and coordinates into the slope-form equation, y = mx + b :

$y = mx + b$

Let m = -4/3,

Let x = -5,

Let y = 6,

$6 = - \frac{ 4}{3} ( - 5) + b$

$6 = \frac{20}{3} + b$

$b = 6 - \frac{20}{3}$

$b = - \frac{2}{3}$