Answer:
No Real Solutions
Step-by-step explanation:
1. You are going to be ”completing the square”, this is in simple terms solving for the x values when you can’t do so with the “original method” of multiplying the a term (first term) and c term (last term) and subtracting/adding to get the middle number.
2. In order to find the square you take the middle term divide it by 2 and multiply it by the power of 2, you take the last term and move it to the other side of the equation.
x^2 + 3x = -7
x^2 + 3x + 9/4 = -7
3. You have tried using the ”complete the square” method and I already mentioned that the “original method“ does not apply to this problem, so you now know that this problem does not have any real solutions
The solution to the required equation [tex]x^2+3x+7=0[/tex] is [tex]\x = \sqrt{-19/4}-3/2[/tex].
The solution to the following equation x^2+3x+7=0 0to be determined.
The equation is the relationship between variables and is represented as y =m ax+b is an example of a polynomial equation.
[tex]x^2+3x+7=0[/tex]
dividing the coefficient of x i.e. 3
=3/2
Now squaring the 3/2 and add and subtract in the equation
[tex]x^2+3x+7+(3/2)^2-(3/2)^2=0\\x^2+3x+9/4=9/4-7\\(x+3/2)^2 = -19/4\\x+3/2 = \sqrt{-19/4}\\x = \sqrt{-19/4}-3/2[/tex]
Thus, the solution to the required equation [tex]x^2+3x+7=0[/tex] is [tex]\x = \sqrt{-19/4}-3/2[/tex].
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