Question

A gas occupies a volume of 2.45 L at a pressure of 1.03 atm. What volume will the
gas occupy if the pressure changes to 0.980 atm and the temperature remains
unchanged? Show your work in the space below. *​

Answer 1

Answer:

2.58 L

Explanation:

Please see the step-by-step solution in the picture attached below.

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Answer 2

At constant temperature, if the pressure of the gas decreases to the given value, the volume increases to 2.58L.

What is Boyle's law?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question

• Initial volume V₁ = 2.45L

• Initial pressure P₁ = 1.03atm

• Final pressure P₂ = 0.980 atm

• Final volume V₂ = ?

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = ( 1.03atm × 2.45L ) / 0.980atm

V₂ = 2.5235Latm / 0.980atm

V₂ = 2.58L

Therefore, at constant temperature, if the pressure of the gas decreases to the given value, the volume increases to 2.58L.

Learn more about Boyle's law here: brainly.com/question/1437490