Question

Some rocket engines use a mixture of hydrazine, N2H4, and hyrdogen peroxide, H2O2, as the propellant. The reaction is given by the following equation:
N2H4 + 2H2O2 --> N2 + 4H2O --balanced
Use your balanced equation to determine the limiting reactant when 10 mol N2H4 is mixed with 10 mol H2O2.
How to solve: Work two calculations. Start with each reactant amount in moles. Solve for one of the products - use the mole ration from the equation. The LR (limiting reactant) is the one that makes the LEAST amount of product.
10 mol N2H4 x 1 mol N2 / 1 mol N2H4 =
10 mol H2O2 x 1 mol N2 / 2 mol H2O2 =

Answer 1

Answer:

H2O2

Explanation:

                          N2H4 + 2H2O2        -------->    N2  + 4H2

from reaction    1 mol      2 mol                       1 mol

given                10 mol    10 mol

needed             10mol      20 mol

We can see from reaction that H2O2 needs 2 times more. For 10 mol N2H4 we have not enough H2O2, so H2O2 is limiting reactant.

2d way:

10 mol N2H4 x 1 mol N2 / 1 mol N2H4 = 10 mol N2

10 mol H2O2 x 1 mol N2 / 2 mol H2O2 = 5 mol N2

H2O2 makes less N2, so H2O2 is a limiting reactant.