I need help with this question below.
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Answer:
Step-by-step explanation:
Three points are specified, not a "shape." We will assume that the "shape" is intended to be a filled triangle with those three points as vertices.
The shape specified by the given coordinates is a right triangle with one leg on the x-axis. Revolving the figure around the x-axis will make a cone. The height of the cone is the length of the leg on the x-axis: 4. The radius of the cone is the length of the leg perpendicular to the x-axis: 2.
The attached figure shows the x-y plane cross section through the revolved figure is an isosceles triangle (BCB'). By the nature of the revolution, cross sections in a y-z plane will be circles centered on the x-axis with a radius equal to the y-value of the edge of the shape.
In summary, the revolved shape is a cone of radius 2 and height 4 with the x-axis as its axis of symmetry.