Two children are playing a code-breaking game. One child makes a sequence of three colors from red, yellow, blue, and purple. The other child must guess the sequence of colors in the correct order. Once one color is used, it cannot be repeated in the sequence.

What is the probability that the sequence is guessed on the first try?

StartFraction 1 Over 24 EndFraction
One-eighth
One-fourth
One-third

Respuesta :

Answer:

1/24

Step-by-step explanation:

i just took it

The probability that the sequence is guessed on the first try is 1/24.

Probability

Total colors available for making code=4

Colors required for making code=3

Hence:

Total ways of making code=4p3=4!/(4-3)!

=4×3×2×1/1

=24

Probability that the sequence is guessed on the first try=1/Total ways of making code

Probability that the sequence is guessed on the first try=1/24

Therefore the correct option is A.

Learn more about probability here:https://brainly.com/question/24756209

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