Question

In a comparison of the body fat percentage of four different ethnic groups, the body fat percentage was measured for 200 African-Americans, 160 Whites, 220 Hispanics, and 310 Others. Because a comparison of average body fat percentage between these groups is desired, an ANOVA test was conducted, which resulted in p-value of 0.11. What conclusion can you make if level of significance is 0.05?

Answer 1

Answer:

There is not enough evidence to support the claim that the fat percentage of at least one of the four ethnic groups is different.

Step-by-step explanation:

The Analysis of Variance (ANOVA) test is used to determine whether there is any significant difference between the mean of various independent groups.

In this case an ANOVA test is being performed to determine whether the fat percentage of four different ethnic groups are different or not.

The hypothesis can be defined as:

H₀: The fat percentage of four different ethnic groups are same, i.e. μ₁ = μ₂ = μ₃ = μ₄.

Hₐ: The fat percentage of at least one of the four ethnic groups is different, i.e. at least one μ$_{i}$ is different.

The significance level of the test is, α = 0.05.

The decision rule is:

• If the p-value of the test is less than the significance level, then the null hypothesis will be rejected.

• And if the p-value of the test is not less than the significance level, then the null hypothesis will not be rejected.

The p-value of the ANOVA test is computed as, p-value = 0.11.

p-value = 0.11 > α = 0.05.

The null hypothesis was failed to be rejected.

Hence, it can be concluded that there is not enough evidence to support the claim that the fat percentage of at least one of the four ethnic groups is different.