Question

According to the Guinness Book of World Records, a woman from Russia, Mrs. Vassilyeva, had 69 children between the years 1725 to 1765. She had 16 pairs of twins, 7 sets of triplets, and 4 sets of quadruplets. Suppose one of the births is randomly selected. Given that Mrs. Vassilyeva gave birth to at least 3 children (triplets), what is the probability that she gave birth to quadruplets

Answer 1

Answer:

36.36% probability that she gave birth to quadruplets

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcoes.

Desired outcomes:

Giving births to quadruplets.

She has 4 sets of quadruplets.

So $D = 4$

Total outcomes:

At least 3 children(triplets).

7 sets of triplets and 4 sets of quadruplets.

So $T = 7 + 4 = 11$

Probability:

$p = \frac{D}{T} = \frac{4}{11} = 0.3636$

36.36% probability that she gave birth to quadruplets

Answer 2

Answer:

(E) 4/11

Step-by-step explanation:

P(Mrs. Vassilyeva gave birth to quadruplets | she gave birth to at least triplets) = 4/11.  

Of the 11 times she gave birth to at least triplets, 4 of those births were quadruplets.