Question

What net ionic equation describes the reaction when these solutions are mixed?

Given the equation: Na3PO4 (aq) + CaCl2(aq) →


A. 2PO43–(aq) + Cl– (aq) → Cl2(PO4)3(s)
B. 2Ca2+(aq) + Na+(aq) → NaCa2(s)
C. Na+(aq) + Cl– (aq) → NaCl(s)
D. 2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Answer 1

I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:

2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Hope this answers the question. Have a nice day.

Answer 2

Answer:

$2PO_{4}^{-3} (aq) + 3Ca^{+2}(aq)-->Ca_{3}(PO_{4})_{2}(s)$

Explanation:

In net ionic equation we remove the spectator ions. The ions which are present on both the side and are not forming any solid compound.

Let us write the balanced reaction first:

$2Na_{3}PO_{4}(aq)+3CaCl_{2}(aq)-->3Ca_{3}(PO_{4})_{2}+6NaCl(aq)$

The ionic reaction is:

$6Na^{+}(aq)++6Cl^{-}(aq)+2PO_{4}^{-3} (aq) + 3Ca^{+2}(aq)-->Ca_{3}(PO_{4})_{2}(s)+6Na^{+}(aq)+6Cl^{-}(aq)$

Thus net ionic reaction is

$2PO_{4}^{-3} (aq) + 3Ca^{+2}(aq)-->Ca_{3}(PO_{4})_{2}(s)$