Respuesta :

[tex]-\dfrac{2}{3}\cdot12\dfrac{3}{8}=-\dfrac{2}{3}\cdot\dfrac{12\cdot8+3}{8}=-\dfrac{2}{3}\cdot\dfrac{99}{8}\\\\=-\dfrac{1}{1}\cdot\dfrac{33}{4}=\boxed{-\dfrac{33}{4}}=-\dfrac{32+1}{4}=\boxed{-8\dfrac{1}{4}}[/tex]
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