Question

Find the distance between points P (-3, 4) and Q (1, 6).

Answer 1

$Let\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B)\ then\ the\ distance\ between\ AB\ is:\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

P(-3; 4); Q(1; 6)

subtitute

$|PQ|=\sqrt{(1-(-3))^2+(6-4)^2}=\sqrt{4^2+2^2}=\sqrt{16+4}=\sqrt{20}\\\\=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5$

Answer: The distance between P and Q is 2√5.

Answer 2

The distance between two points are $\sqrt{20}$ unit.

Distance :

The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is computed as,

                   $Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

Given points are, P (-3, 4) and Q (1, 6).

Substitute points in above formula.

                $Distance=\sqrt{(1+3)^{2}+(6-4)^{2} } \\\\Distance=\sqrt{16+4} =\sqrt{20}$

The distance between two points are $\sqrt{20}$ unit.

Learn more about the distance between points here:

https://brainly.com/question/24775607