Question

Find the coordinates of the midpoint of HX given that H(-1,3) and X(7,-1)

A.(3,1)
B.(0,4)
C.(-3,1)
D.(-4,0)

Answer 1

The midpoint of AB where $A(x_A;\ y_A)$ and $B(x_B;\ y_B)$

$\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

$H(-1;\ 3);\ X(7;-1)$

The midpoint of HX: $\left(\dfrac{-1+7}{2};\ \dfrac{3+(-1)}{2}\right)=\left(\dfrac{6}{2};\ \dfrac{2}{2}\right)=(3;\ 1)$

Answer: A(3, 1)