Question

A balloon contains 6.0 moles of helium. A hole lets 4.0 moles of helium escape the balloon. How many atoms of helium remain in the balloon?

A.2.0 atoms
B.1.2 x10^24 atoms
C.6.02 x 10^24 atoms
D.6.0 Atoms

Answer 1

d. it is the answer to the question

Answer 2

Answer : The number of atoms of helium atom remain in the balloon are, $1.2\times 10^{24}$

Explanation : Given,

Moles of helium present in balloon = 6.0 mole

Moles of helium escape from balloon = 4.0 mole

First we have to calculate the moles of helium remains in the balloon.

Moles of helium remains in the balloon = Moles of helium present in balloon - Moles of helium escape from balloon

Moles of helium remains in the balloon = 6.0 - 4.0 = 2.0 mole

Now we have to calculate the number of helium atoms remain in the balloon.

As, 1 mole of helium atom remain in the balloon contains $6.022\times 10^{23}$ number of helium atoms.

So, 2.0 mole of helium atom remain in the balloon contains $2.0\times 6.022\times 10^{23}=12.044\times 10^{23}=1.2\times 10^{24}$ number of helium atoms.

Therefore, the number of helium atom remain in the balloon are, $1.2\times 10^{24}$