Question

Which value for x makes the open sentence true? 6 • 7 – 5x + x2 ≥ x3 + x2

Answer 1

6●7–5x+x2≥x3+x2 Lets plug in 3: 6●7–5(3)+32≥33+32 Multiply -5 * 3: 6●7–15+32≥33+32 Simplify all exponents: 6●7–15+9≥27+9 Multiply 6 * 7: 42–15+9≥27+9 Subtract 42 - 15: 27+9≥27+9 Add 27 + 9: 36≥27+9 Add 27 + 9: 36≥36 So 3 is correct.