Question

1.) a current-carrying conductor of length 0.8 m is placed perpendicular to the direction of the magnetic field of 0.6 tesla. what is the value of the current in the conductor if the conductor experiences a force of 1.2 n? 2.5 a 1.6 a 1.2 a 0.4 a 2.) an electron moves to the east and enters the magnetic field. the direction of the magnetic field is perpendicular to the direction of velocity acting downward. what is the direction of the force the electron experiences? east west north south

Answer 1

1. The current can be calculated using the equation :

Force = current × length of wire × magnetic field strength

Plug in all the values

1.20 = current × 0.80 × 0.60

Simplify

1.20 = current × 0.48

Isolate for current

current = 2.5 Amps

2. electron moves east
magnetic field is downwards

the velocity, field and force all all perpendicular to each other. You can use the straight fingered left hand rule to determine the direction of the force.

Point your index finger to the right side (east), point your middle finger down towards the ground while you keep your index finger in place. You're left with your thumb pointing towards you, which is the south direction.

The direction of the force is south

Answer 2

The correct answer is:     south