Answer: [tex]1\dfrac{1}{13}[/tex]
Step-by-step explanation:
Given : The wingspan of the butterfly : [tex]3\dfrac{1}{4}\text{ inches}=\dfrac{13}{4}\text{ inch}[/tex]
The length of moth = [tex]3\dfrac{1}{2}\text{ inches}=\dfrac{7}{2}\text{ inches}[/tex]
To find the number of times larger is the moth than the butterfly, we divide the length of moth by the wingspan of the butterfly as :_
[tex]\dfrac{7}{2}\div\dfrac{13}{4}\\\\=\dfrac{7}{2}\times\dfrac{4}{13}=\dfrac{14}{13}=1\dfrac{1}{13}[/tex]
Hence, the moth is [tex]1\dfrac{1}{13}[/tex] times larger than the butterfly.
