Respuesta :
We assume that the sun is all hydrogen for this or the amount other components are negligible. The calculations are as follows:
2.0x10^30 kg of sun x ( 1.67x10^-27 kg hydrogen atom / 1 kg of sun ) = 3340 kg hydrogen atom
3340 kg hydrogen atom ( 1000 g / 1 kg ) ( 1 mol H/ 1.01 g H ) = 3306930.693 mol H
3306930.693 mol H x (6.022 x 10^23 atoms / 1 mol ) = 1.99 x 10^30 atoms H
2.0x10^30 kg of sun x ( 1.67x10^-27 kg hydrogen atom / 1 kg of sun ) = 3340 kg hydrogen atom
3340 kg hydrogen atom ( 1000 g / 1 kg ) ( 1 mol H/ 1.01 g H ) = 3306930.693 mol H
3306930.693 mol H x (6.022 x 10^23 atoms / 1 mol ) = 1.99 x 10^30 atoms H
Answer: The number of hydrogen atoms in Sun is [tex]1.2\times 10^{57}[/tex]
Explanation:
We are given:
Mass of Sun = [tex]2.0\times 10^{30}kg[/tex]
Mass of hydrogen atom = [tex]1.67\times 10^{-27}kg[/tex]
To calculate the number of hydrogen atoms, we divide the mass of Sun to the mass of hydrogen atom, we get:
[tex]\text{Number of hydrogen atom}=\frac{\text{Mass of Sun}}{\text{Mass of hydrogen atom}}[/tex]
Putting values in above equation, we get:
[tex]\text{Number of hydrogen atoms}=\frac{2.0\times 10^{30}kg}{1.67\times 10^{-27}kg}=1.2\times 10^{57}[/tex]
Hence, the number of hydrogen atoms in Sun is [tex]1.2\times 10^{57}[/tex]