Respuesta :
We can calculate years by using the half-life equation. It is expressed as:
A = Ao e^-kt
where A is the amount left at t years, Ao is the initial concentration, and k is a constant.
From the half-life data, we can calculate for k.
1/2(Ao) = Ao e^-k(1620)
k = 4.28 x 10^-4
0.125 = 1 e^-4.28 x 10^-4 (t)
t = 4259 years
A = Ao e^-kt
where A is the amount left at t years, Ao is the initial concentration, and k is a constant.
From the half-life data, we can calculate for k.
1/2(Ao) = Ao e^-k(1620)
k = 4.28 x 10^-4
0.125 = 1 e^-4.28 x 10^-4 (t)
t = 4259 years
Answer:
4860 years
Explanation:
From
N/No = (1/2)^t/t1/2
Where:
No= mass as time t=0
N= mass at time t
t= time
t1/2= half life
0.125/1 = (1/2)^t/1620
1/8 = (1/2)^t/1620
(1/2)^3= (1/2)^t/1620
3= t/1620
t= 3×1620
t= 4860 years