If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4=dcba. The digits a, b, c and d are all different. Find abcd. That means what numbers are abcd equal to?

Respuesta :

The given is that A B C D x 4 = D C B A

Possible values of A are 1 or 2. It can't be 1 since the 
 final result A is in unit place and 1 is not possible when we multiply any number by 4

2 B C D x 
4 = D C B 2
It is clear above, that D = 8
2 B C 8 x 4 = 8 C B 2
Possible values of B should be 1 or 2
We try B=1

2 1 C 8 x 4 = 8 C 1 2

To find for C, you can use the equation:

(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,

C = 7
So, the number is 2178.

Answer:

The number is 2178, multiplied by 4 gives 8712.

Step-by-step explanation:

Let us say the number is written as abcd [tex](1000a+100b+10c+d)[/tex]   .....(1)

When you multiply it by 4, it gives dcba [tex](1000d+100c+10b+a)[/tex]

Now, [tex]4\times(abcd)=dcba[/tex]

We get;

[tex]4000a+400b+40c+4d =1000d+100c+10b+a[/tex]

=> [tex]3999a+390b=996d+60c[/tex]

=> [tex]1333a+130b= 20c+332d[/tex]     ......(2)

Now, we can relate few properties:

The first digit is a quarter of the last one as d=4a .

or [tex]a=d/4[/tex]

or [tex]a=0.25d[/tex]

The second digit is one less than the first.  

[tex]b=(a-1)[/tex]

Now, from equation 2, we get

[tex]1333a+130b= 20c+332d[/tex]

Replacing b and d, we get

[tex]1333a+130a-130=20c+1328a[/tex]

=> [tex]135a=20c+130[/tex]

=> [tex]27a=4c+26[/tex]

or, [tex]a =(4/27)c+(26/27)[/tex]

There is only one single digit integer solution.

c = 7; a = 2

Now,  

[tex]b =2-1[/tex]=1 and  d =4(2) =8

Hence, 2178 is the number.

And we can see that [tex]4\times2178= 8712[/tex]

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