Respuesta :
The given is that A B C D x 4 = D C B A
Possible values of A are 1 or 2. It can't be 1 since the final result A is in unit place and 1 is not possible when we multiply any number by 4
2 B C D x 4 = D C B 2
It is clear above, that D = 8
2 B C 8 x 4 = 8 C B 2
Possible values of B should be 1 or 2
We try B=1
2 1 C 8 x 4 = 8 C 1 2
To find for C, you can use the equation:
(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,
C = 7
So, the number is 2178.
Possible values of A are 1 or 2. It can't be 1 since the final result A is in unit place and 1 is not possible when we multiply any number by 4
2 B C D x 4 = D C B 2
It is clear above, that D = 8
2 B C 8 x 4 = 8 C B 2
Possible values of B should be 1 or 2
We try B=1
2 1 C 8 x 4 = 8 C 1 2
To find for C, you can use the equation:
(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,
C = 7
So, the number is 2178.
Answer:
The number is 2178, multiplied by 4 gives 8712.
Step-by-step explanation:
Let us say the number is written as abcd [tex](1000a+100b+10c+d)[/tex] .....(1)
When you multiply it by 4, it gives dcba [tex](1000d+100c+10b+a)[/tex]
Now, [tex]4\times(abcd)=dcba[/tex]
We get;
[tex]4000a+400b+40c+4d =1000d+100c+10b+a[/tex]
=> [tex]3999a+390b=996d+60c[/tex]
=> [tex]1333a+130b= 20c+332d[/tex] ......(2)
Now, we can relate few properties:
The first digit is a quarter of the last one as d=4a .
or [tex]a=d/4[/tex]
or [tex]a=0.25d[/tex]
The second digit is one less than the first.
[tex]b=(a-1)[/tex]
Now, from equation 2, we get
[tex]1333a+130b= 20c+332d[/tex]
Replacing b and d, we get
[tex]1333a+130a-130=20c+1328a[/tex]
=> [tex]135a=20c+130[/tex]
=> [tex]27a=4c+26[/tex]
or, [tex]a =(4/27)c+(26/27)[/tex]
There is only one single digit integer solution.
c = 7; a = 2
Now,
[tex]b =2-1[/tex]=1 and d =4(2) =8
Hence, 2178 is the number.
And we can see that [tex]4\times2178= 8712[/tex]