Question

How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?
A. 4.1498 × 1024
B. 4.1498 × 1023
C. 8.299 × 1024
D. 8.299 × 1023

Answer 1

I believe there would be A. 4.1498x10^24 formula units in 6.89 moles of KOH.

Answer 2

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of formula units or atoms or molecules into number of moles.

6.89 mol KOH (6.022 x 10^23 formula units / mole) = 4.1498 x 10^24 formula units

Therefore, the correct answer is option A.