Question

Divide (18x^3 + 12x – 3x) ÷ 6x^2

Answer 1

18$x^{3} +9x$÷$6x^{2}$
=$\frac{18 x^{3}+9x }{ 6x^{2} }$
=$\frac{9x(2 x^{2} +1)}{6 x^{2} }$
=$\frac{3(2 x^{2} +1)}{2x}$

Answer 2

we can first simplify the numerator which is 18x^3 + 12x – 3x into 18x^3 + 9x. The simplified numerator adds the the same terms which is 12x and -3x. In this case, we can factor 9x in the numerator into 9x ( 2x2 + 1). We can cancel 3x from the numerator and the denominator. Hence the final expression results to 3 ( 2x2 + 1) / 2x.