Find mJPK Geometry circles will mark brainliest
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Answer:
53.13
Step-by-step explanation:
mJKL = sin-1(9/15) = 36.9 deg
mKJL = = 36.9 deg ...base angles of isosceles triangle JKL
mJLK = 180 - 36.9 - 36.9 = 106.26 deg
mJPK = mJLK/2 = 106.29/2 = 53.1 deg......half of central angle