Please help with this. Thanks
I need to find the degree
![Please help with this Thanks I need to find the degree class=](https://us-static.z-dn.net/files/d2b/11d2deddd5d8fb4e62aa7ea896792bbc.png)
Answer:
119.06°
Step-by-step explanation:
The direction the vector makes with the x- axis is
Θ = [tex]tan^{-1}[/tex]( [tex]\frac{9}{-5}[/tex] ) ≈ - 60.945°
Since the vector is in the second quadrant, then
Θ = 180° - 60.945° ≈ 119.06° ( to the nearest hundredth )