Given circle T, and tangents AD and CD, what is the measure of angle ADC?
![Given circle T and tangents AD and CD what is the measure of angle ADC class=](https://us-static.z-dn.net/files/de7/565e2eb0d76277304f97c62095c6251a.jpeg)
Answer:
The measure of angle ∡ADC is 36°
Step-by-step explanation:
Here answer the question, we draw C to meet T and A to T to form an angle ∡ATC;
We note that the angle subtended at the center of a circle is two times that of the angle at the circumference, therefore ∡ATC = ∡ABC = 2 × 72 = 144 °
Also ∡TCD = ∡TAD = 90° Angle between radius and a tangent
Therefore, ∡ATC + ∡TCD + ∡TAD + ∡ADC = 360° (Sum of interior angles of a polygon)
Which gives; 144 + 90 + 90 + ∡ADC = 360
∴ ∡ADC = 360 -324 = 36°
The measure of angle ∡ADC = 36°.