Question

- How many moles of HCl will be needed to neutralize 200.0 ml of a 2.5 M NaOH solution?

Answer 1

Answer:

0.5 mol HCl

Explanation:

2.5 mol/L *0.200 L = 0.5 mol NaOH

                         NaOH + HCl ---> NaCl + H2O

from reaction   1 mol      1 mol

given                 0.5mol    x mol

x= 0.5*1/1= 0.5 mol HCl