The amount of three-dimensional space enclosed by a closed surface is known as volume. The code is 240.
What is volume?
The amount of three-dimensional space enclosed by a closed surface is expressed as a scalar quantity called volume.
1. The volume of a cylinder with a radius of 7 ft and a height of 5 ft is,
[tex]\rm \text{Volume of Cylinder} = \pi r^2 h = \pi \times 49 \times 5=769.7\ ft^3[/tex]
2. The Volume of the Pyramid with a side 12m, while the height is 9m is,
[tex]\rm \text{Volume of Pyramid} = \dfrac13 \times (\text{Area of square}) \times height = \dfrac13 \times 12^2 \times 9 = 432\ m^3[/tex]
3. The volume of the sphere with a diameter of 9 yds, can be written as,
[tex]\rm \text{Volume of sphere}=\dfrac{4}{3} \pi r^3=\dfrac43 \times \pi \times (\dfrac{9}{2})^3=381.7\ yd^3[/tex]
4. The surface area of the cuboid with a length of 16 cm, width of 5 cm, and height of 11 cm can be written as,
[tex]\rm \text{Surface area of Cuboid} = 2[(L\times W)+(W\times H)+(L\times H)][/tex]
[tex]\rm \text{Surface area of Cuboid} = 2[(16\times 5)+(5\times 11)+(16\times 11)] = 622\ cm^2[/tex]
5. The surface area of the given figure can be written as,
Surface Area of figure = 2(Area of the triangle) + Area of slant side + Area of rectangle + Area of base
[tex]\rm \text{Surface Area of figure} = (\dfrac{2 \times 5 \times 18}{2}) + (18.7 \times 7)+(18 \times 7) + (5 \times 7) = 381.9\ in^2[/tex]
6. The surface area of a cone is given as,
[tex]\text{Surface Area of Cone}=\pi r(\sqrt{h^2+r^2})+\pi r^2[/tex]
The radius of the cylinder is 8 mm while the height is 15 mm, therefore, the surface area can be written as,
[tex]\rm\text{Surface Area of Cone}=\pi \times 8(\sqrt{15^2+8^2})+\pi \times 8^2 = 628.3\ mm^2[/tex]
Now, if we fill the results accordingly in fill in the blanks we will get,
Starting with 60, divide by 5
then add by 13
then multiply by 3
and subtract by 11
Now, cube root your result 64
Multiply the starting number60.
Thus, the code is 240.
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