Question

When 5 is subtracted from the square of a number, the result is 4 times the number. Find the negative solution.

Answer 1

Answer:

$x=-5\\x=1$

Step-by-step explanation:

$5-x^2=4x$

subtract 4x on both sides.

$5-x^2-4x=0$

$-x^2-4x+5=0$

Since x cannot be negative, multiply by -1.

$(-1)(-x^2-4x+5=0)\\x^2+4x-5=0$

$(x+5)(x-1)=0$

$x+5=0\\x=-5$

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$x-1=0\\x=1$

Answer 2

The negative solution is - 1.

let

the number = x

When 5 is subtracted from the square of a number can be represented as follows;

• x²-5

The result is 4 times the number. The remaining part of the equation can be represented as follows:

• x²-5 = 4x

Lets find the negative solution below

x²- 5 - 4x = 0

x² - 4x - 5 = 0

x² + x - 5x - 5 = 0

x(x + 1) -5(x + 1)

(x-5)(x + 1)

x = 5 or -1

Therefore, the negative solution is - 1.

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