Question

Question 5 (1 point)
A gas in a 100 L tank at 25 degrees Celsius exerts a pressure of 19 atm. The gas is cooled to 0 degrees Celsius and pumped into a 20 L tank.
What pressure will it exert under these new conditions?
OOOO
35 atm
46 atm
87 atm
104 atm​

Answer 1

Answer : The pressure it exert under these new conditions will be, 87 atm

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 19 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 100 L

$V_2$ = final volume of gas = 20 L

$T_1$ = initial temperature of gas = $25^oC=273+25=298K$

$T_2$ = final temperature of gas = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get:

$\frac{19atm\times 100L}{298K}=\frac{P_2\times 20L}{273K}$

$P_2=87atm$

Therefore, the pressure it exert under these new conditions will be, 87 atm