Answer:
D.
C.
A,B
Step-by-step explanation:
Given:
Diameter of a cone-shaped kitchen funnel = 6 inches
Height of a cone-shaped kitchen funnel = 7 inches
Radius of a cylindrical funnel = 4 inches
Height of a cylindrical funnel = 13 inches
To find: Number of cylindrical funnels required to fill a cone-shaped kitchen funnel
Solution:
Radius of a cone-shaped kitchen funnel (R) = 6/2 = 3 inches
Height of a cone-shaped kitchen funnel (H) = 7 inches
Volume of a cone-shaped kitchen funnel = [tex]\frac{1}{3}\pi R^2H=\frac{1}{3}\pi(3)^2(7)=21\pi[/tex] cubic inches
Radius of a cylindrical funnel (r) = 4 inches
Height of a cylindrical funnel (h) = 13 inches
Volume of a cylindrical kitchen funnel = [tex]\pi r^2h=\pi(4)^2(13)=208\pi[/tex] cubic inches
Number of cylindrical funnels required to fill a cone-shaped kitchen funnel = 9.9≈ 10
Option D. is correct
Given:
Circumference of an orange = 37.68 centimeters
To find: volume of the orange
Solution:
Let r be the radius of the orange
Circumference of an orange = 37.68 centimeters
[tex]2\pi r=37.68\\r=\frac{37.68}{2\pi}[/tex]
Volume of the sphere = [tex]\frac{4}{3}\pi r^3[/tex]
[tex]=\frac{4}{3}\pi \left ( \frac{37.68}{2\pi} \right )^3[/tex]
[tex]=\frac{4}{3}\frac{\left ( 37.68 \right )^3}{8(3.14)^2}=904.32[/tex] cubic metres
Volume of sphere can be computed using only the radius or using only the diameter.
Option A and B are correct.
For volume of cone, both radius and height are required
