Respuesta :
Answer:
[tex]x=\frac{19}{12}\\ or\\x=\frac{5}{12}[/tex]
Step-by-step explanation:
[tex]6x^2-x-2=0[/tex]
a=6
b=-1
c=-2
[tex]x=-b\frac{+}{}\frac{\sqrt[]{b^2-4ac} }{2a}[/tex]
[tex]x=-(-1)\frac{+}{}\frac{\sqrt[]{(-1)^2-4(6)(-2)} }{2(6)}[/tex]
[tex]x=1\frac{+}{}\frac{\sqrt[]{1+48} }{12}[/tex]
[tex]x=1\frac{+}{}\frac{\sqrt[]{49} }{12}[/tex]
[tex]x=1\frac{+}{}\frac{7}{12}[/tex]
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[tex]x=1+\frac{7}{12}[/tex]
[tex]x=1-\frac{7}{12}[/tex]
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[tex]1+\frac{7}{12}=\frac{(1*12)+(7*1)}{12} =\frac{12+7}{12} =\frac{19}{12}[/tex]
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[tex]1-\frac{7}{12}=\frac{(1*12)-(7*1)}{12} =\frac{12-7}{12} =\frac{5}{12}[/tex]
