Answer:
The answer is "180,000, 6, and 90"
Explanation:
The answer to this question can be described as follows:
[tex]\ force = 12,000 \ lb \\\\\ distance = 15 \ ft \\\\ \ Formula : \\\\ \ total \ work = force \times distance \\\\ \ IMA = \frac{load}{effort} \\\\\ OR \\\\ \ IMA = \frac{\ distance \ move \ by \ load }{\ distance \ moved \ by \ efforts}[/tex]
[tex]a ) \\\\\ total \ work = 12,000 \times 15 \\\\\ total \ work = 180,000 ft \cdot lbf[/tex]
[tex]b) \\\\IMA = \frac{12000}{2000} = 6 \\\\ c) \\\\IMA = \frac{Y}{15} \\\\6= \frac{Y}{15}\\\\Y= 90\\\\X = \sqrt{8100-225}\\\\X = \sqrt{90^2-15^2} \\\\X= \sqrt{7875} \\\\X =88.74 ft\\\\[/tex]
by comparing the length of the ramp is 90 ft.